dy/dx = 1/x-y

来源：学生作业帮编辑：拍题作业网作业帮分类：数学作业时间：2024/04/27 08:30:06

dy/dx = 1/x-y

这个先要换元,凡是对于dy/dx=f(ax+by+c)这类微分方程先令u=ax+by+c.
对于本题,就是令u=x-y,则dy/dx=1-du/dx,1/x-y=1/u,分别代入就可解出来.

dy/dx = 1/x-y dy/dx=x(1-y) dy/dx=x+y (x^2)dy+（y^2)dx=dx-dy 微分方程(x+y)(dx-dy)=dx+dy的通解求解dy/dx=(x+y)/(x+y+1) dy/dx,y=(1+x+x^2)e^x 设y=（x/1-x)^x,求dy/dx 解, Dy/Dx + y = x , y(0) = 1 dy/dx=x(1+y^2)/y通解 cos(x+y)+y=1 求dy/dx dy/dx-2y/(1+x)=(x+1)^3