cos(x+y)+y=1 求dy/dx
cos(x+y)+y=1 求dy/dx
y= (cos x)^x,求dy/dx
对于x=cos(y/x),求dy/dx.
ysinx-cos(x+y)=0,求 dy/dx
设函数y=y(x)由方程cos(x+y)+y=1确定,求dy/dx
设y=y(x)由方程cos(x+y)+y=1确定,求dy/dx
dy/dx=cos(x+y+1)常微分方程
dy/dx=cos(x+y+1)
设y=cos(2x^2+x+1) 求dy/dx. 过程
设 y=y(x)由方程cos(x)+y=1确定,求dy/dx
x=θ(1-sinθ) y=θcosθ 求dy/dx
dx/dy=x/y+[cos(x/y)]∧2,y(0)=1