log2^x >= log4^(3x+4)

来源：学生作业帮编辑：拍题作业网作业帮分类：数学作业时间：2024/04/26 08:09:08

log2^x >= log4^(3x+4)
log2 跟 log4怎样化同底数啊哎对你们应该很简单吧 .希望有好人帮到我,
底数是 2 和 4

我的对,看清楚
log2^x>= log4^(3x+4) ==> log2^x>= log2^(3x+4)/log2^4 ==>
2log2^x>=log2^(3x+4) ==> log2^(x^2)>=log2^(3x+4) ==>
x^2>=3x+4

log2^x >= log4^(3x+4) log4(log2^x)=log2(log4^x)求log2^x log2^x=log4^9 求解log2 (3X+2)-log4 (X)=3 解方程log2(2x)*log4(x/4)=2 log4(13-3x)=log2(x-1) 解方程：log2(3-x) - log4(x+5) =1 log2(x-2)=log4(5-x) 对数问题 log2^x=log4^9 若log2^3×log3^4×log4^x=log9^3 ,求x log2^x=log4^x,则x= 1.log2(x)=log4(x),求x