(d^2 y/d^2 x)/(dy/dx)= -(1/x)求特解
(d^2 y/d^2 x)/(dy/dx)= -(1/x)求特解
从(dx)/(dy)=1/y '导出:(d^2x)/(dy^2)=-y''/(y')^3
试从dx/dy=1/y'导出:d^2x/dy^2=-y''/(y')^3 题目中关于d[1/y']/dx}*[dx/dy
dx/dy=1/y',求d^2x/dy^2 .为什么d^2x/dy^2不等于dx/dy求导?一个是二阶导数,一个是一阶导
已知dx/dy=1/y′,求d(2)y/d x^2?
d^2y/dx^2=(dy/dx)'×(dy/dx),另外请解释下dx,dy的含义,dx和dy是指x=...和y=...
已知dx/dy=1/y',求证1、d^2x/dy^2=-y''/(y')^3.2、d^3x/dy^3=[3(y'')^2
y=[sin(x^4)]^2,则dy/dx=?,dy^2/dx^2=?,dy/d(x^2)=?
d(x+y)=dx+dy,
d/dx((x^2+y^2)^2)=d/dx(x^2-y^2),求(化简)dy/dx=?
试从dx/dy=1/y'导出:d^2x/dy^2=-y''/(y')^3.d^2x/dy^
求微分方程的通解:x^2(d^2y/dx^2)=(dy/dx)^2+2x(dy/dx)