设函数f(x)有界,又lim(x→∞)g(x)=0,证明:lim(x→∞)f(x)g(x)=0(证明过程)
设函数f(x)有界,又lim(x→∞)g(x)=0,证明:lim(x→∞)f(x)g(x)=0(证明过程)
证明lim[f(x)^g(x)]=[limf(x)]^lim[g(x)]
设lim f(x) = A ,lim g(x) = B.用极限定义来证明lim[f(x) ● g(x)] = lim f
已知 lim(x->+∞)f'(x)=0 证明:lim(x->+∞)f(x)=常数
设函数f(x)在(a,+∞ )上可导,且lim(x->+∞ )(f(x)+f'(x))=0,证明:lim(x->+∞ )
当x→a时,lim f(x) =+∞,当x→+∞,lim g(x)=A,证明:当x→a时,lim g(f(x))=A
若函数f(x),g(x)满足lim[f(x)-g(x)]=0,x-∞,则limf(x)=limg(x),x-∞
设f(x)有二阶导数,且f''(X)>0,lim(x趋于0)f(x)/x=1 ..证明:当x>0时,有f(x)>x
f(x)是定义在(0,+∞)上的连续可微函数,且lim(x->+∞)(f(x)+f ' (x))=0,证明lim(x->
设limf(x)=0,且g(x)=0,证明lim(f(x)/g(x))=C(常数不等于0)的逆命题会证,
证明lim[f(x)+g(x)]=limf(x)+limg(x)
lim[f(x)+g(x)]=limf(x)+limg(x)如何证明