将函数y=根号3cosx sinx(x∈R)的图像向左平移M

f(x)=sin2x+根号3乘cos2x答案：-2小于等于f（x）小于等于2需要用和角公式和求极值的方法（数学书上都有）

f(x)=2cosxsin(x+60°)-√3sin²x+sinxcosx=2cosx(sinxcos60º+cosxsin60º)-√3sin²x+sinxc

f(x)=sinxcosx+sqrt(3)(cosx)^2-sqrt(3)(sinx)^2+sinxcosx+2=2sinxcosx+sqrt(3)[(cosx)^2-(sinx)^2]=sin2x+

f(x)=2cosx[1/2sinx+√3/2cosx]-√3sin^2(x)+sinxcosx=sinxcosx+√3cos^2(x)-√3sin^2(x)+sinxcosx=sin2x+√3cos

f(x)=2cosxsin(x+π/3)-√3sin^2x+sinxcosx=2cosx(1/2*sinx+√3/2*cosx)-√3sin^2x+sinxcosx=sinxcosx+√3cos^2x

【1】f(x)=2cosx[(1/2)sinx+(√3/2)cosx]-√3sin²x+sinxcosx+1=cosxsinx+√3cos²x-√3sin²x+sinxc

f(x)=2cosxsin(x+π)-sqrt(3/2)=-2cosxsinx-sqrt(3/2)=-sin2x-sqrt(3/2)最小正周期=2π/2=π

2cosxsin(x+π/3)=2cosx(sinxcosπ/3+cosxsinπ/3)=cosxsinx+√3cos^2xf(x)=cosxsinx+sinxcosx+√3(cos^2x-sin^2

注：所有无理数“派”用pi表示f(x)=2cosxsin(x+π/3)-√3(sinx)^2+sinxcosx=2cosx(sinx/2+√3cosx/2)-√3(1-cos2x)/2+sin2x/2

y=2cosxsin(x+π/3)-根号3*(sin^2)x+sinxcosx,后两项先提出一个sinx,然后括号内部分用叠加原理,得到y=2cosxsin(x+π/3)+2sinxcos(x+π/3

f(x)=2cosxsin(x+π/3)-√3/2=2cosx[sinx*(1/2)+cosx(√3/2）]-√3/2=sinxcosx+√3cos^2x-√3/2=(1/2)sin(2x)+(1/2

y=2sin²x-√3sinxcosx+cos²x=sin²x-√3sinxcosx+(sin²x+cos²x)=(1-cos2x)/2-√3/2*s

f(x)=2cosxsin(x+π/3)-√3sin^2x+sinxcosx=2cosx(√3/2sinx+1/2cosx)-√3sin^2x+1/2sin2x=√3/2sin2x+cos^2x-√3

你好!先化简f(x)=2cosxsin(x+π/3)-√3*(sinx)^2+sinxcosx=2cosx[sinxcos(π/3)+cosxsin(π/3)]-√3*(sinx)^2+sinxcos

f(x)=2cosxsin(x+π/3)-√3sin^2x+sinxcosx=cosx(sinx+√3cosx)-√3(sinx)^2+sinxcosx=2sinxcosx+√3[(cosx)^2-(

f(x)=2cosxsin(x+π/3)-√3sin²x+sinxcosx=2cosx[sinxcos(π/3)+cosxsin(π/3)]-√3sin²x+sinxcosx=2c

f(x)=2cosxsin(x+π/3)-√3*(sinx)^2+sinxcosx=2cosx[sinxcos(π/3)+cosxsin(π/3)]-√3*(sinx)^2+sinxcosx=sinx

公式：2sinAcosB=sin(A+B)+sin(A-B)f(x)=2cosxsin(x+π/3)-√3/2=sin(x+π/3+x)+sin(x+π/3-x)-√3/2=sin(2x+π/3)+√

最大值2,最小值－2.通过化简,化成一个三角函数式,即可知道结果.请参考图片.