f(x)=cos(2x-π/3)+2sin(x-π/4)怎么化简成(sinx-cosx)(sinx+cosx)
f(x)=cos(2x-π/3)+2sin(x-π/4)怎么化简成(sinx-cosx)(sinx+cosx)
化简f(x)=4sinx*sin^2((π+2x)/4)+(cosx+sinx)(cosx-sinx)
f(x)=2cos*sin(x+π/3)-^3sin^2x+sinx*cosx
sinx+cosx/sinx-cosx=2 求sinx/cos^3x +cosx/sin^3x
已知函数f(x)=cos(2x-π/3)+(cosx+sinx)(cosx-sinx)
已知函数f(x)=2cosx*sin(x+π/3)-√3sin^2x+sinx*cosx
设f(x)=2cosx.sin(x+π/3)-根号3 sin平方x+sinx.cosx
已知sinx+cosx/2sinx-3cosx=3 求 2sin²x-3sin(3π+x)cos(π-x)-3
已知sinx+cosx/sinx-cosx=2,求2cos(π-x)-3sin(π+x)/4cos(-x)+sin(2π
2sin(x-π/4)sin(x+π/4)=(sinx-cosx)(sinx+cosx)=-cos2a
a=(2cosx,sinx),b=(sin(x+3分之π),cosx-根号下3sinx),f(x)=a×b.求函数f(x
证明定积分(0到π/2)sin^3x/(sinx+cosx)dx=定积分(0到π/2)cos^3x/(sinx+cosx