∫1/（sinx+cosx）dx,

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∫1/（sinx+cosx）dx,

∫1/（sinx+cosx）dx
=(√2/2)∫1/[(√2/2)sinx+(√2/2)cosx] dx
=(√2/2)∫1/sin(x+π/4) dx
=(√2/2)∫csc(x+π/4) dx
=(√2/2)ln|csc(x+π/4)-cot(x+π/4)|+C

∫1/（sinx+cosx）dx, ∫[（sinx-cosx）/1+sin2x]dx ∫1/（sinx cosx）dx ∫/(1+sinx+cosx)dx ∫（cosx/1+sinx)dx ∫sinx（cosx+1）/（1+cosx^2）dx ∫(1+sinx)/(1+cosx+sinx)dx ∫cosx / (cosx+sinx)dx ∫dx/（sinx+cosx) ∫(sinx-cosx)dx ∫ sinx+cosx/(sinx-cosx)^1/3 dx 求不定积分求积分：∫ sinx*sinx/(1+cosx*cosx)dx