lim(x趋向于0)(cosx)^[1/(xsinx)]=

来源：学生作业帮编辑：拍题作业网作业帮分类：数学作业时间：2024/04/28 17:29:49

lim(x趋向于0)(cosx)^[1/(xsinx)]=lim(x趋向于0)[(1+cosx-1)^(1/(cosx-1))]^[(cosx-1)/(xsinx)]
=lim(x趋向于0)e^[(cosx-1)/(xsinx)]
=e^lim(x趋向于0)[(cosx-1)/(xsinx)]
=e^lim(x趋向于0)[-sinx/(x+xcosx)]
=e^(-0.5)

lim(x趋向于0)(cosx)^[1/(xsinx)]= 1-√cosx/xsinx 求Lim X趋向于0 X趋向0 lim(xsinx)/(1-cosx) 1.lim(sinx)^2/√(1+xsinx)-√cosx x趋向于0 lim x趋向于0 根号1+xsinx -根号cosx/xtanx lim e-e^cosx除以xsinx x趋向0 大数lim(cosx)^(1/(1-cosx)).x趋向于0 lim(cosx)^(1/(1-cosx)).x趋向于0 求,x趋近于0时,lim[根号下(1+xsinx)-cosx]/x的平方= lim x→0 1-cosx/xsinx x趋向于0,求极限lim((tankx)/(xsinx)) 求极限lim[e^xsinx-x(1+x)]/x^3 其中X趋向于0