化简:2sin^4x+3\4sin^2(2x)+5cos^4x-1\2(cos4x+cos2x)

（2010•泰安一模）已知函数f(x)＝4cos4x−2cos2x−1sin(π4+x)sin(π4−x) 化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x f(x)=(1+cos2x)/[4sin(pai/2+x)]-asin(x/2)cos(pai-x/ 已知函数f(x)=(6cos^4x+5sin^2x-4)/cos2x cos^4(x)-sin^4(x)等于?是cos^2(x)还是cos2x (1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x 设f(x)=(sin^4 x-cos^4 x-5)/(cos2x+2). (a)证明f(x)= 3/(2 sin^2 x 求证:sin(π/4+x)/sin(π/4-x)+cos(π/4+x)/(π/4-x)=2/cos2x 已知函数f(x)=（4cos^4x-2cos2x-1）/[sin(π/4+x)·sin^2(π/4-x)]化简 已知函数f(x)=（4cos^4x-2cos2x-1）/[sin(π/4+x)·sin(π/4-x)]化简 1.y=cos^4x+sin^4x 求周期 2.y=（sin2x+sin（2x+π/3)）/（ cos2x+cos（2x 化简2sin^2[(π/4)+x]+根号3（sin^x-cos^x）-1