x−2y+4z=123x+2y+z=14x−z=7
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
x+y−2z=52x−y+z=42x+y−3z=10
解方程组:5x−4y+4z=132x+7y−3z=193x+2y−z=18
己知x,y,z,t满足方程组x+y+z=62x−z+t=−2
解方程组x−4y=0x+2y+5z=22x+y+z=12
3x+4z=7①2x+3y+z=9 ②5x−9y+7z=8 ③
已知x−y+z=0x+2y−3z=0
2x+y+3z=383x+2y+4z=564x+y+5z=66
若x+2y-4z=0 3x+y-z=0 求x:y:z
解方程组:3x+2y+5z=2x−2y−z=64x+2y−7z=30.
解方程组(1)x+y−z=6x−3y+2z=13x+2y−z=4
解方程组:x−2y+4z=172x+y+z=33x+y−2z=−5