2x+y+3z＝383x+2y+4z＝564x+y+5z＝66

2x+y+3z＝383x+2y+4z＝564x+y+5z＝66 x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, 三元方程求救要过程2x+3y+z=383x+4y+2z=564x+5y+z=66x:y=5:3x:z=7:32x-y-z 若x+2y-4z＝0 3x+y-z＝0 求x：y：z 十万火急!4x-9z＝17 3x+y+15z＝18 x+2y+3z＝ x+2y+3z＝12x+3y+z＝23x+y+2z＝3 x+y−2z＝52x−y+z＝42x+y−3z＝10 x/2=y/3=z/5 x+3y-z/x-3y+z 1.（x+y-z)+(x-y+z)-(x-y-z) 2.2x-(3x-2y+3)-(5y-2) 已知x／2＝y／3＝z／5,且3x＋4z－2y＝40,求x、y、z的值﹔详解 解方程组：5x−4y+4z＝132x+7y−3z＝193x+2y−z＝18 x－y－z＝0 ｛x＋y－3z＝4 2x－5y＋7z＝21 三元一次方程解