关于对数运算(lg5)^2+lg2·lg50=?(log2 125+log4 25+log8 5)·(log125 8+
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关于对数运算
(lg5)^2+lg2·lg50=?
(log2 125+log4 25+log8 5)·(log125 8+log25 4+log5 2)=?
(lg5)^2+lg2·lg50=?
(log2 125+log4 25+log8 5)·(log125 8+log25 4+log5 2)=?
(lg5)^2+lg2·lg50
=(lg5)^2+lg2*(lg5+1)
=lg5*(lg5+lg2)+lg2
=lg5*lg10+lg2
=lg5+lg2
=lg10
=1
(log2 125+log4 25+log8 5)·(log125 8+log25 4+log5 2)
=((lg125/lg2)+(lg25/lg4)+(lg5/lg8))((lg8/lg125)+(lg4/lg25)+lg2/lg5))
=(3(lg5/lg2)+(lg5/lg2)+(lg5/lg2)*(1/3))((lg2/lg5)+(lg2/lg5)+(lg2/lg5))
=(13/3)(lg5/lg2)*3(lg2/lg5)
=13
=(lg5)^2+lg2*(lg5+1)
=lg5*(lg5+lg2)+lg2
=lg5*lg10+lg2
=lg5+lg2
=lg10
=1
(log2 125+log4 25+log8 5)·(log125 8+log25 4+log5 2)
=((lg125/lg2)+(lg25/lg4)+(lg5/lg8))((lg8/lg125)+(lg4/lg25)+lg2/lg5))
=(3(lg5/lg2)+(lg5/lg2)+(lg5/lg2)*(1/3))((lg2/lg5)+(lg2/lg5)+(lg2/lg5))
=(13/3)(lg5/lg2)*3(lg2/lg5)
=13
关于对数运算(lg5)^2+lg2·lg50=?(log2 125+log4 25+log8 5)·(log125 8+
高中数学对数计算求值(log2 125+log4 25+log8 5)*(log125 8+log25 4+log5 2
[log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)]
[log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)
(Log2 125+log4 25+log8 5)(log5 2+log25 4+log125
(lg5)^2+lg2·lg50=?
高中对数运算求出(lg5)^2+lg2*lg50的值,
对数运算:(lg5)的平方+lg2*lg50根号下(lg5的平方-2lg5+1)
计算(lg5)^2+lg2·lg50
(1)已知lg2=a,lg3=b,试用a,b表示对数lg18/25 (2)(lg5)^2+lg2·lg50
(lg5)^2 + (lg2)*(lg50)=
对数(lg5)^2+lg50*lg2怎么做,还有关对数运算公式