暑假作业因式分解(x+y-2xy)(x+y)+(xy-1)2

来源：学生作业帮编辑：拍题作业网作业帮分类：数学作业时间：2024/04/27 20:08:22

暑假作业因式分解(x+y-2xy)(x+y)+(xy-1)2
急,最后的2是（xy-1)的平方的意识
变成(x+y-2xy)(x+y-2)+(xy-1)2

x+y-2XY)(x+y-2)+(xy-1)^2
=[（x+y)-2xy][(x+y)-2]+(xy-1)^2
=(x+y)^2-2(xy+1)(x+y)+4xy+x^2y^2-2xy+1
=(x+y)^2-2(xy+1)(x+y)+x^2y^2+2xy+1
=(x+y)^2-2(xy+1)(x+y)+(xy+1)^2
=[(x+y)-(xy+1)]^2
=(x+y-xy-1)^2
=[x(1-y)-(1-y)]^2
=(x-1)^2(1-y)^2
=(x-1)^2(y-1)^2

暑假作业因式分解(x+y-2xy)(x+y)+(xy-1)2 （xy-x-y+1)^2因式分解 y^3+xy^2+2xy+x^2-1 因式分解因式分解xy²-2xy+x+2y-1 因式分解xy+y平方+x-y-2 x^2+y^2-x-y-xy+1如何因式分解因式分解：x×x-xy-2y×y-x-y xy+x+y+1因式分解 1-x-y+xy 因式分解因式分解xy-x-y+1 xy-x-y+1因式分解因式分解(x+y)^3+2xy(1-xx-y)-1