5sina=3sin(a-2β)求证tan(a-β)+4tanβ=0
5sina=3sin(a-2β)求证tan(a-β)+4tanβ=0
5sinA=3sin(A+2B),求证tan(A+B)=4tanB
已知3sinβ=sin(2a+β),求证:tan(a+β)=2tana
为什么 tan a +1/tan a=sin^2 a +cos^2 a/(sina cos a)
求解 已知 sin(a+b)=1/2 ,sin(a_b)=1/3,求证:tan a=5tan b
已知sin(a+β)=1/2,sin(a-β)=1/3,则tan²βtan(a+β)分之(tan(a+β)-t
已知(tan a-3)(sin a+cos a+3)=0,求值:(4sina-2cosa)/(5cosa+3sina)
求证sin与tan 已知3sinB=sin(2A+B),求证tan(A+B)=2tanA
若sina+sinβ=a,cosa+cosβ=b,则tan(a/2)+tan(β/2)=
已知sina=3sin(α+β),求证:tan(α+β)=sinβ/(cosβ)-3
tan^2a =2tan^2b+1 求证 cos2a +sin^2b=0
已知3*sina=2*sin(2*a+b),a+b,ak*pai+pai/2,k属于整数,求证tan(a+b)=5*ta