4(x-1)=5x+10的解是几?
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)的导数在x=1
4(x-1)=5x+10的解是几?
求函数y=\x-1\+\x-2\+\x-3\+\x-4\+\x-5\+\x-6\+.+\x-10\的最小值
1)x+1/x=3,求x^10+x^5+1/x^5+1/x^10的值
已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^5+x^6+x^7+x^8的值
x的平方-2x+1=15 ; x(2x-5)=4x-10 ; x的平方+5x+7=3x=11
设函数f(x)=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10),
计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1
(1) x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8
3/x-1=4/x 6/x+1=x+5/x(x+1)
C语言中编写s=1-x+(x*x)/2!-(x*x*x)/3!+(x*x*x*x)/4!知道最后一项的绝对值小于10的-
计算:1/(x^2-7x+10)+1/(x^2-x-2)+1/(x^2+5x+4)+1/(x^2+11x+28)=( )