证明:tan(α+π/4)+tan(α+3π/4)=2tan2α
证明:tan(α+π/4)+tan(α+3π/4)=2tan2α
证明 tan(π/4+α)-cot(π/4+α)=2tan2α
求证:tan(a+π/4)+tan(a-π/4)=2tan2α
已知α=π/9,求值tanα+tan2α+根号3tanα×tan2α=( )
tan(α+π/4)=2,则cos2α+3sin^2α+tan2α=?
化简tan2αtan(π/6-α)+tan2αtan(π/3-α)+tan(π/6-α)tan(π/3-α)=?请写下过
已知tan(α+β)=3,tan(α-β)=2,求2α,tan2β的值
已知tanα=3,α属于(π/4,π/2)求sin2α,cos2α,tan2α的值
1.已知tan2分之α=2,求值:⑴ tan(α+4分之π);⑵ (6sinα+cosα)/(3sinα-2cosα)
tan(π/4+α)=2010,那么1/cos2α+tan2α=
证明tanα-1/tanα等于2/tan2α 现等
已知tanα=2,求sin(π/4+α)/cos(π/4+α)·tan2α的值