f(x)=x∧2 sinx展开为x的幂级数,其含x∧7项的系数

来源：学生作业帮编辑：拍题作业网作业帮分类：数学作业时间：2024/05/15 23:38:42

g(x) = sinx
g'(x) = cosx
g''(x) = -sinx
g'''(x)= -cosx
g''''(x) = sinx
g'''''(x) = cosx
g(x) = g(0) +(g'(0)/1!)x +(g''(0)/2!)x^2+.
f(x) = x^2.sinx
= g(0) x^2+(g'(0)/1!)x^3 +(g''(0)/2!)x^4+.
coef.of x^7
=g^(5)(0)/5!
=1/5!
=1/120

f(x)=x∧2 sinx展开为x的幂级数,其含x∧7项的系数 (sinx)^2展开成x的幂级数将函数展开为幂级数将函数f(x)=1/(x²+x-2)展开成X的幂级数将f(x)=1/(x∧2-4x-5)展开成x的幂级数将f(x)=1/x^2-4x+3展开为x的幂级数并写出其收敛域展开幂级数f(x)=x/1+x-2x^2展成X的幂级数函数f(x)=(sinx)^2展开成x的幂级数将函数f(x)=sinx/2展开成x的幂级数函数f(x)=1/x^2+3x+2展开为x+3的幂级数将f(x)=sinx/x展开成x的幂级数, 将f(x)=x|x*x+x-2展开成x的幂级数函数f(x)=x/(2-x)展开成x的幂级数f(x)