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这些初二计算题怎么写?步骤要出来,

来源:学生作业帮 编辑:拍题作业网作业帮 分类:数学作业 时间:2024/05/15 05:45:18
这些初二计算题怎么写?步骤要出来,
x²-(x-y)²
(x+2y)²-(2x-y)²
(x+y+z)²-(x-y-z)²
(a-b) ^4-(b-a)²
x²-(x-y)²
=x²-x²+2xy-y²
=2xy-y²
(x+2y)²-(2x-y)²
=x²+4xy+4y²-4x²+4xy-y²
=3y²+8xy-3x²
(x+y+z)²-(x-y-z)²
=(x+y+z-x+y+z)(x+y+z+x-y-z)
=(2y+2z)*2x
=4xy+4xz
(a-b) ^4-(b-a)²
=(a-b)²[(a-b)²-1)
=(a²-2ab+b²)(a²-2ab+b²-1)
=a^4-2a³b+a²b²-a²-2a³b+4a²b²-2ab³+2ab+a²b²-2ab³+b^4-b²
=a^4-4a³b+6a²b²-a²-4ab³-b²+^4
再问: 能把他修改改成分解因式的形式么,我在给你加10~20分··
再答: 可以。 x²-(x-y)² =(x-x+y)(x+x-y) =y*(2x-y) =2xy-y² (x+2y)²-(2x-y)² =(x+2y-2x+y)(x+2y+2x-y) =(3y-x)(3x-y) =9xy-3x²-3y²-xy =8xy-3x²-3y²(x+y+z)²-(x-y-z)² =(x+y+z-x+y+z)(x+y+z+x-y-z) =(2y+2z)*2x =4xy+4xz (a-b) ^4-(b-a)² =(a-b)²[(a-b)²-1) =(a²-2ab+b²)(a²-2ab+b²-1) =a^4-2a³b+a²b²-a²-2a³b+4a²b²-2ab³+2ab+a²b²-2ab³+b^4-b² =a^4-4a³b+6a²b²-a²-4ab³-b²+^4