(sec^2x-sinx+1/x-1/(1+x^2))dx
(sec^2x-sinx+1/x-1/(1+x^2))dx
∫(sec^2x+sinx)dx
∫secx/sec^2x-1 dx
∫1/根号x*sec^2(1-根号x)dx
1、∫[2/(1+x^2) -sec^2)dx
∫1/(sec^2x+1)dx等于多少?
∫[(sec^2x-1)secx]dx=
∫ sec^2 x dx
∫sec²x/1+tanx dx
求不定积分(1)dx/√x(1+√x)(2)dx/e^x+(e^-x)+2 (3)(tan^5x*sec^4x)dx
∫(1+sinx) / cos^2 x dx
=∫dx/(2cos^2(x/2)+1)=∫sec^(x/2)dx/(2+sec^2(x/2))怎么出来的?