(x+1)(x+3)(x+5)(x+7)-9怎么因式分解啊

来源：学生作业帮编辑：拍题作业网作业帮分类：数学作业时间：2024/05/01 07:53:55

(x+1)(x+3)(x+5)(x+7)-9
=[(x+1)(x+7)][(x+3)(x+5)]-9
=(x^2+8x+7)(x^2+8x+15)-9
=(x^2+8x+7)[(x^2+8x+7)+8]-9
=(x^2+8x+7)^2+8(x^2+8x+7)-9
=[(x^2+8x+7)+3][(x^2+8x+7)+5]
=(x^2+8x+10)(x^2+8x+12)
=(x^2+8x+10)(x+2)(x+6)

(x+1)(x+3)(x+5)(x+7)-9怎么因式分解啊 (x-1)(x-3)(x-5)(x-7)-9 因式分解因式分解 (x+1)(x+3)(x+5)(x+7)+15 (x^2+5x+9)(x^2-3x+7)-3(4x+1)因式分解 (x-1)(x-3)+1怎么因式分解因式分解：x^9+x^8-x^6-x^5+x^3+x^2-1 (x-1)(x-3)(x-5)(x-7)-9 因式分解,要用换元法（x+1)(x+2)(x+5)(x+7)+15 因式分解因式分解 (x+1)(x+2)(x+5)(x+7)+15 1+X^3怎么因式分解啊? 因式分解 (x+1)(x-3) 因式分解：(x+1)^3-9(x+1)