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已知方程3x²-4x=-1的两根是x1 x2,不解方程,求:1.x2/x1 + x1/x2 2.(x1 - 2

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已知方程3x²-4x=-1的两根是x1 x2,不解方程,求:1.x2/x1 + x1/x2 2.(x1 - 2)(x2 - 2)
方程3x²-4x=-1可化为:3x²-4x+1=0
由根与系数的关系,有
x1+x2=4/3, x1x2=1/3
∴x2/x1 + x1/x2
=(x1²+x2²)/(x1x2)
=[(x1+x2)²-2x1x2]/(x1x2)
=[(4/3)²-2×(1/3)]/(1/3)
=[(16/9)-(2/3)]/(1/3)
=(10/9)/(1/3)
=10/3

(x1-2)(x2-2)
=x1x2-2x1-2x2+4
=x1x2-2(x1+x2)+4
=(1/3)-2×(4/3)+4
=(1/3)-(8/3)+4
=(-7/3)+4
=5/3.