用标根法解不等式(1)2x²+x-6/(x-1)²(x+1)≤0 (2)-1≤3x/x²-
用标根法解不等式(1)2x²+x-6/(x-1)²(x+1)≤0 (2)-1≤3x/x²-
(x²-5x+6分之x²-3x+2)²/(x²-2x-3分之x-1)²
(1)(x²-2x)²+2(x²-2x)+1
(x²-2x)²+2x²-4x+1
计算:[(x²-2x+1)/(x²-1)]÷[(x-1)(x²+x)]-x
计算 2(x²-x+1)-(-2x+3x²)+(1-x)
计算题:3x(x²-3x+2)-x²(3x-1)
y=(x²+1)²/[(3x²+2)(2x²+3)],求最小值
先化简再求值x²-x/(x+1)×x²-1/(x²-2x+1)
2(x²-1²)
再求代数式(4x²-7x+6y-1)-(-2x²+3y²+2y+2x)+(-6x²
(2x²-3x+1)²-22x+33x-1怎么做?