已知{an}中a1=1/5,当n∈N且n≥2时a(n-1)/an=[2a(n-1)+1]/(1-2an)
已知{an}中a1=1/5,当n∈N且n≥2时a(n-1)/an=[2a(n-1)+1]/(1-2an)
已知数列{an}中a1=6,且an-an-1=(an-1/n)+n+1(n属于N*,n≥2),求an
已知数列an中满足a1=1且当n.=2时,2an*a*(n-1)+an-a(n-1)=0,求通项公式an
已知数列{An}中a1=1.且A(n+1)=6n*2^n-An.求通项公试An
已知数列an中,a1=5,且an=2a(n-1)+2^n-1(n大于等于2,n属于正整数)
已知数列{an}中,a1=1,a(n+1)>an,且[a(n+1)-an]^2-2[a(n+1)+an]+1=0,则an
已知数列an中,a1=1 2a(n+1)-an=n-2/n(n+1)(n+2) 若bn=an-1/n(n+1)
若数列{an},a1=2/3,且a(n+1)=an+1/【(n+2)(n+1)】,(n∈N+)则通项an=?
1.已知数列{An}满足A1=1,An= 2A(n-1)+2(n∈N,且N≥2)
在数列{An}中,已知An+A(n+1)=2n (n∈N*)
已知数列{an}中,a1=1,an+a(n+1)=2^n(n∈N*),bn=3an
已知数列{an}满足a1=1/5,且当n>1,n∈N*时,有a(n-1)/an=2a(n-1)+1/1-2an,设bn=