1/(12)+1/(23)+1/(34)+.1/(20072008)=?

来源：学生作业帮编辑：拍题作业网作业帮分类：数学作业时间：2024/05/20 08:07:55

1/(1*2)+1/(2*3)+1/(3*4)+.1/(2007*2008)=?

将(2-1)/1*2断开,变成两个分式相减
(2-1)/1*2=2/1*2 - 1/1*2
在约分
=1-1/2
同样的,(3-2)/2*3=3/2*3 - 2/2*3 = 1/2 - 1/3
所以最后是
(1-1/2) + (1/2-1/3) + (1/3-1/3) + ...+ (1/2007-1/2008)
因为是加法,所以可以把括号全部拿掉
就是1-1/2+1/2-1/3+1/3-...+1/2007-1/2008=1-1/2008=2007/2008

1-(1/2-1/3)-(1/3-1/4).-(1/2007-1/2008)=? 1/1*2+1/2*3+1/3*4+1/4*5.+1/2007*2008+1/2008*2009=? 1/(1*2)+1/(2*3)+1/(3*4)+.1/(2007*2008)=? 1/(1*2)+1/(2*3)+1/(3*4)+.1/(2007*2008)= 1\(2\3)\(3\4)\.\(2007\2008) |1-1/2|+|1/2-1/3|+|1/3-1/4|+……|1/2007-1/2008|=? (-1)+2+(-3)+4+(-5)+.+(-2007)+2008 -1-2-3-4-5-...-2007-2008 初一数学计算题1/1*2+1/2*3+1/3*4+1/4*5+.+1/2007*2008=? 1/2009-1/2008|+|1/2008-1/2007|+|1/2007-1/2006|+.+|1/3-1/2|+| |2009/1-2008/1|+|2008/1-2007/1|+|2007/1-2006/1|+.+|3/1-2/1|+ 计算:|1/2-1|+|1/3-1/2|+|1/4-1/3|+...+|1/2008-1/2007|+|1/2009-1