f(x)=2cos2x+sin^2x,化简.详细步骤!
f(x)=2cos2x+sin^2x,化简.详细步骤!
已知函数f(x)=2cos2x+sin²x
已知f(sin-1)=cos2x+2,求f(x)
f(x)=((1+cos2x)^2-2cos2x-1)/(sin(π/4+x)sin(π/4-x))
已知函数f(x)=sin(π-x)sin(π2-x)+cos2x
f(x)=sin(2x-5/6π)+2cos2x化简
化简f(x)=2cos2x+sin^2x-4cosx
一条高中的数学题: 化简: F(x)=2cos2x+sin²x-4cox
f(X)=2cos2x+sin²x-4cosx化简
f(x)=sin(2x+3派\2) 怎么变成 f(x)=-cos2x
f(x)=(1+cos2x)/[4sin(pai/2+x)]-asin(x/2)cos(pai-x/
2cos2x+sin^2x 化简