ln(1+2x^2)/ln(1+3x^3) lim趋向于正无穷,用洛必达法则求它的极限
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ln(1+2x^2)/ln(1+3x^3) lim趋向于正无穷,用洛必达法则求它的极限
答:
lim(x→+∞) ln(1+2x^2) / ln(1+3x^2)
=lim(x→+∞) [4x /(1+2x^2)] / [ 6x/(1+3x^2) ]
=lim(x→+∞) (2/3)*(1+3x^2) / (1+2x^2)
=(2/3)*(3/2)
=1
再问: 是ln(1+3x^3)
再答: 答: lim(x→+∞) ln(1+2x^2) / ln(1+3x^3) =lim(x→+∞) [4x /(1+2x^2)] / [ 9x^2/(1+3x^3) ] =lim(x→+∞) (4/9)*(1+3x^3) / [x(1+2x^2)] =(4/9) lim(x→+∞) (9x^2) / (1+6x^2) =(4/9)*(9/6) =2/3
lim(x→+∞) ln(1+2x^2) / ln(1+3x^2)
=lim(x→+∞) [4x /(1+2x^2)] / [ 6x/(1+3x^2) ]
=lim(x→+∞) (2/3)*(1+3x^2) / (1+2x^2)
=(2/3)*(3/2)
=1
再问: 是ln(1+3x^3)
再答: 答: lim(x→+∞) ln(1+2x^2) / ln(1+3x^3) =lim(x→+∞) [4x /(1+2x^2)] / [ 9x^2/(1+3x^3) ] =lim(x→+∞) (4/9)*(1+3x^3) / [x(1+2x^2)] =(4/9) lim(x→+∞) (9x^2) / (1+6x^2) =(4/9)*(9/6) =2/3
ln(1+2x^2)/ln(1+3x^3) lim趋向于正无穷,用洛必达法则求它的极限
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