计算log9(根号2)*[log4(3)+log8(3)]
计算log9(根号2)*[log4(3)+log8(3)]
计算:(log4 3+log8 3)×log9 √2=?
(log4(3)+log8(3))(log3(2)+log9(2))-log4(3)×log1/3(四次根号32)
计算:(log4 9+log8 3)(log3 2+log9 2)-log1/3 4√81
化简(log4(3)+log8(3))(log3(2)+log9(2))
(log4^3+log8^3)(log3^2+log9^2)
求值(log4(3)+log8(3))×(log3(2)+log9(2))
求值(log3(2)+log9(2))*(log4(3)+log8(3))
(log3 2+log9 2)*(log4 3+log8 3)求值
(log3^2 + log9^4)×(log4^3 + log8^3)
求值:(log4^ 3+log8 ^9)*(log3^ 2+log9 ^16)
计算(log2 3+log4 9+log8 27+……+log2^n 3^n)log9 n次根号3