(1)(1/(x-10))+(1/(x-6))=(1/(X-7))+(1/(x-9))
来源:学生作业帮 编辑:拍题作业网作业帮 分类:数学作业 时间:2024/04/29 11:01:12
(1)(1/(x-10))+(1/(x-6))=(1/(X-7))+(1/(x-9))
(2)((x+1)/(x-2))-((x+2)/(X+3))=(1/(x+7))-(1/(x-6))
(2)((x+1)/(x-2))-((x+2)/(X+3))=(1/(x+7))-(1/(x-6))
y=(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)(x-10)
y'={(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)}(x-10)+{(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)}(x-10)'
y'(10)={(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)}(x-10)'
=x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)
(x=10)
y'={(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)}(x-10)+{(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)}(x-10)'
y'(10)={(x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)}(x-10)'
=x-1)(x-2)(x-3)(x-4)(x-5)(x-6)(x-7)(x-8)(x-9)
(x=10)
(1) x-3/x-2 - x-5/x-4=x-7/x-6 - x-9/x-8
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