CAN PLAY!已知向量AB=(1-tanx,1+tanx),AC=(sin(x-π/4),sin(x+π/4))(1
CAN PLAY!已知向量AB=(1-tanx,1+tanx),AC=(sin(x-π/4),sin(x+π/4))(1
已知向量AB=(1+tanx,1-tanx),向量AC=(sin(x-π/4),sin(x+π/4)
已知向量AB=(1+tanX,1-tanX),向量AC=(sIn(X-45度),sin(X+45度)).(1)求证向量A
高中数学竞赛题,已知向量AB=(1+tanx,1-tanx)向量AC=[sin(x-45°),sin(x+45°)],求
已知函数fx=(1+1/tanx)sin^x-2sin(x+π/4)sin(x-π/4)
已知函数f(x)=(1+1/tanx)sin(x)^2 -2sin(x+π/4)*cos(x+π/4)
已知2tanx/1+tanx的平方=3/5求sin(π/4+x)的平方的值
已知2tanx/1+tanx=3/5,求sin(π/4+x)的值 过程
已知函数f(x)=(1+1/tanx)sin2x-2sin(x+π/4)sin(x-π/4)
已知COS(π/4-X)=-4/5,求(SIN2X-2SIN^X)/(1+TANX)
已知(2sin^2x+sin2x)/(1+tanx)=1/2(π/4
已知函数f(x)=(1+1/tanx)sin^2-2sin(x+π/4)sin(x-π/4).求tana=2时,f(a)