1.(X+3)^4+(X+1)^4=82
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1.(X+3)^4+(X+1)^4=82
2.X+(X+1)^(1/2)=7
3.2X^4+3X^3-16X^2+3X+2=0
X+Y=-20
4.{
(X-1)^(1/3)+(Y+2)^(1/3)=-1
^是因为无法把指数写小而用的特殊符号。^后的数字就是指数。
如题中(X+3)^4就是(X+3)的4次方; (X+1)^(1/2)就是根号(X+1);(X-1)^(1/3)就是(X-1)的3次方根。
2.X+(X+1)^(1/2)=7
3.2X^4+3X^3-16X^2+3X+2=0
X+Y=-20
4.{
(X-1)^(1/3)+(Y+2)^(1/3)=-1
^是因为无法把指数写小而用的特殊符号。^后的数字就是指数。
如题中(X+3)^4就是(X+3)的4次方; (X+1)^(1/2)就是根号(X+1);(X-1)^(1/3)就是(X-1)的3次方根。
我 也 来 试 一 试 :
1.(X+3)^4+(X+1)^4=82
==》(X+3)^2(X+3)^2+(X+1)^2(X+1)^2=82
==》2X^4+16X^3+60X^2+112X+82=82
==>2X^4+16X^3+60X^2+112X=0
==》X(X^3+8X^2+30X+56)=0
==>X=0 or -4
2.X+(X+1)^(1/2)=7
==》(X+1)^(1/2)=7-X
==》X+1=(7-X)^2
==>14X=48
==>X=24/7
3.2X^4+3X^3-16X^2+3X+2=0
==》(X-2)(2X^3+7X^2-2X-1)=0
==》(X-2)(2X-1)(X^2+4X+1)=0
==》(X-2)(2X-1)((X+2)^2-3)=0
==》X=2,or 1/2 or 3^(1/2)-2
4.X+Y=-20 (1)
(X-1)^(1/3)+(Y+2)^(1/3)=-1(2)
由(2)式得:
(X-1)^(1/3)=-1-(Y+2)^(1/3)
==》X-1=【-1-(Y+2)^(1/3)】^3 (3)
将(1)X=-20-Y代入(3)得:
-21-Y=【-1-(Y+2)^(1/3)】^3 (4)
展开化简(4)得:
(Y+2)^(1/3)+(Y+2)^(2/3)=6 (5)
设:(Y+2)^(1/3)=t
则(5)为:t^2+t-6=0
姐方程得:t=-3 or 2.
因此:Y=-29 or 6,
则:X=9 or -27.
1.(X+3)^4+(X+1)^4=82
==》(X+3)^2(X+3)^2+(X+1)^2(X+1)^2=82
==》2X^4+16X^3+60X^2+112X+82=82
==>2X^4+16X^3+60X^2+112X=0
==》X(X^3+8X^2+30X+56)=0
==>X=0 or -4
2.X+(X+1)^(1/2)=7
==》(X+1)^(1/2)=7-X
==》X+1=(7-X)^2
==>14X=48
==>X=24/7
3.2X^4+3X^3-16X^2+3X+2=0
==》(X-2)(2X^3+7X^2-2X-1)=0
==》(X-2)(2X-1)(X^2+4X+1)=0
==》(X-2)(2X-1)((X+2)^2-3)=0
==》X=2,or 1/2 or 3^(1/2)-2
4.X+Y=-20 (1)
(X-1)^(1/3)+(Y+2)^(1/3)=-1(2)
由(2)式得:
(X-1)^(1/3)=-1-(Y+2)^(1/3)
==》X-1=【-1-(Y+2)^(1/3)】^3 (3)
将(1)X=-20-Y代入(3)得:
-21-Y=【-1-(Y+2)^(1/3)】^3 (4)
展开化简(4)得:
(Y+2)^(1/3)+(Y+2)^(2/3)=6 (5)
设:(Y+2)^(1/3)=t
则(5)为:t^2+t-6=0
姐方程得:t=-3 or 2.
因此:Y=-29 or 6,
则:X=9 or -27.
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