2x-y=2,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y

来源：学生作业帮编辑：拍题作业网作业帮分类：数学作业时间：2024/04/29 18:51:38

先化简[(x²+y²)-(x-y)²+2y(x-y)]/4y
[(x²+y²)-(x-y)²+2y(x-y)]/4y
=[x²+y²-(x²+y²-2xy)+2xy-2y²]/4y
=[x²+y²-x²-y²+2xy+2xy-2y²]/4y
=[4xy-2y²]/4y
=[4x-2y]/4
=2*(2x-y)/4
=(2x-y)/2
=1

2x-y=2,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y 已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y |x+2y+3|+(2x+y)²=0求x²-xy+y² x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy 已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y的值已知x²+4x+y²-10y+29=0 求【x+2y】÷【x²-2y²】的值已知x²+y²-4x+6y+13=0,求x²+2y/x²-3y²的值 x²-4y² x+2y 已知x/y=3,求x²+2xy-3y²/x²-2xy+y² x/y=2,求分式x²-xy+3y²/x²+xy+6y² 已知x/y=3,求x²+2xy-3y²/x²-xy+y²的值已知3x²+xy-2y²=0(x≠0,y≠0),求x/y-y/x-x²+y²/x