作业帮已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y
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已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y
已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y 就是已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y /4y就是除以4y
已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y 就是已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y /4y就是除以4y
先化简[(x²+y²)-(x-y)²+2y(x-y)]/4y
[(x²+y²)-(x-y)²+2y(x-y)]/4y
=[x²+y²-(x²+y²-2xy)+2xy-2y²]/4y
=[x²+y²-x²-y²+2xy+2xy-2y²]/4y
=[4xy-2y²]/4y
=[4x-2y]/4
=2*(2x-y)/4
=2*10/4
=5
[(x²+y²)-(x-y)²+2y(x-y)]/4y
=[x²+y²-(x²+y²-2xy)+2xy-2y²]/4y
=[x²+y²-x²-y²+2xy+2xy-2y²]/4y
=[4xy-2y²]/4y
=[4x-2y]/4
=2*(2x-y)/4
=2*10/4
=5
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