sin^6а+cos^6а+3sin²аcos²а化简
sin^6а+cos^6а+3sin²аcos²а化简
已知tanα=-3/4,计算:2sin²а+3sinаcosа-cos²а
化简:sin^6α+cos^6α+3sin^2α*cos^2α=?
1.化简sin²α+cosαcos(π/3+α)-sin²(π/6-α)
已知tanα=3,求4sin²α+3sinα×cos+6cos²α的值.
三角函数题2sin^2α-cos^α+sinα*cosα-6sinα+3cosα=0 求(2cos^α+2sinαcos
化简:(sin²αtanα+cos²α/tanα+2sinαcosα)sinαcosα
sin²α+√3sinαcosα-2cos²α=0,α∈(π/6,5π/12),求:(1)sin(2
化简sin²θ-cos²θ
化简sin²α-2sinαcosα+1
化简(sinα+cosα)²
已知tan=2,求sinα+cosα/2sinα-cosα sin²α+sinαcosα+3cos²