y= ∫[0,x](t-1)^3(t-2)dt,dy/dx(x=0)
y= ∫[0,x](t-1)^3(t-2)dt,dy/dx(x=0)
x=f(t) y=g(t) 为什么dy/dx=(dy/dt)*(dt/dx)
求解dx/(x+t)=dy/(-y+t)=dt
设f(x)连续,Y=∫0~X tf(x^2-t^2)dt 则dy/dx=?
用matlab ode45求微分方程组 dx/dt+x+y=0 dy/dt+x-y=0 x(0)=0 y(0)=1 t=
求dy/dx,y=∫sin(t^2)dt由1/x积到根号x
求该函数对x的导数 y=∫ (1,-x ) sin(t^2) dt ,求dy/dx
设由∫(0,y)e^(2t)dt-∫(0,x)arcsintdt=xy 确定了隐函数y=y(x)则 dy/dx=
dx/dt=x+t,dy/dt=-y+t,求x,y(t为常数).
已知 x=e^t ,dy/dx=dy/xdt .分析变换具体步骤 d^2y/dx^2=(d^2y/dt^2-dy/dt)
求由∫ _0^y(e^t)dt+∫ _0^x(cost)dt=0所决定的隐函数对x的导数dy/dx.
证明x^2(d^2y/dx^2)+a_1x(dy/dx)+a_2y=0 ,令x=e^t,方程可化成d^2y/dt^2+(