证明当x趋向0时,有1.arctanx~x2.secx-1~1/2x^2求答案
证明当x趋向0时,有1.arctanx~x2.secx-1~1/2x^2求答案
证明:当x趋向于1时,有:arctanx~x
证明:当x趋向于0时,有:arctanx~x
求极限x趋向0, x * arctanx - (1/2)ln(1+x2)/x^2
求lim x趋向于0(arctanx)/(x^2+1)
证明当x>0时,arctanx+1/x>π/2
当x>0时,证明:arctanx+1/x>π/2,
当X趋向于0时 证明lim arctanX/X=1
limx趋向0[ln(1+x^2)/secx-cosx]
证明:当x>0,有不等式arctanx+1x
求lim(arcsinx·arctanx)/2x2的极限,x趋向于0
arctanx+arbsin(2x/1+x2)=兀怎么证明?