sin^2x (2cosx sinx)积分

f(x)=sin2x+根号3乘cos2x答案：-2小于等于f（x）小于等于2需要用和角公式和求极值的方法（数学书上都有）

f(x)=2cosxsin(x+60°)-√3sin²x+sinxcosx=2cosx(sinxcos60º+cosxsin60º)-√3sin²x+sinxc

f(x)=sinxcosx+sqrt(3)(cosx)^2-sqrt(3)(sinx)^2+sinxcosx+2=2sinxcosx+sqrt(3)[(cosx)^2-(sinx)^2]=sin2x+

f(x)=2cosxsin(x+π/3)-√3sin^2x+sinxcosx=2cosx(1/2*sinx+√3/2*cosx)-√3sin^2x+sinxcosx=sinxcosx+√3cos^2x

原式=2cosx（0.5sinx+0.5x(根号3)xcosx)-(根号3)x(sinx)x(sinx)+sinxcosx=2sinxcosx+(根号3)x(cosx)x(cosx)-(根号3)x(s

【1】f(x)=2cosx[(1/2)sinx+(√3/2)cosx]-√3sin²x+sinxcosx+1=cosxsinx+√3cos²x-√3sin²x+sinxc

2cosxsin(x+π/3)=2cosx(sinxcosπ/3+cosxsinπ/3)=cosxsinx+√3cos^2xf(x)=cosxsinx+sinxcosx+√3(cos^2x-sin^2

f(x)=2cosxsin(x+π/3）-√3sin^2x+sinxcos=sin(x+π/3+x）+sin(x+π/3-x）-√3(1-cos^2x)+sinxcos=sin(x+π/3+x）+si

y=2cosxsin(x+π/3)-根号3*(sin^2)x+sinxcosx,后两项先提出一个sinx,然后括号内部分用叠加原理,得到y=2cosxsin(x+π/3)+2sinxcos(x+π/3

这个我会.骚后上图.再答：

f(x)=2cosxsin(x+π/3)-√3sin^2x+sinxcosx=2cosx(√3/2sinx+1/2cosx)-√3sin^2x+1/2sin2x=√3/2sin2x+cos^2x-√3

有公式sin(a+b)=sinacosb+cosasinb所以sin(x+π/3)=sinxcosπ/3+cosxsinπ/3=1/2sinx+√3/2cosx

你好!先化简f(x)=2cosxsin(x+π/3)-√3*(sinx)^2+sinxcosx=2cosx[sinxcos(π/3)+cosxsin(π/3)]-√3*(sinx)^2+sinxcos

f(x)=2cosxsin(x+π/3)-√3*(sin²x)+sinxcosx=2cosx(sinxcosπ/3+cosxsinπ/3)-√3*(sin²x)+sinxcosx=

f(x)=2cosxsin(x+π/3)-√3sin^2x+sinxcosx=cosx(sinx+√3cosx)-√3(sinx)^2+sinxcosx=2sinxcosx+√3[(cosx)^2-(

f(x)=2cosxsin(x+π/3)-√3sin²x+sinxcosx=2cosx[sinxcos(π/3)+cosxsin(π/3)]-√3sin²x+sinxcosx=2c

f(x)=2cosxsin(x+π/3)-√3*(sinx)^2+sinxcosx=2cosx[sinxcos(π/3)+cosxsin(π/3)]-√3*(sinx)^2+sinxcosx=sinx

最大值2,最小值－2.通过化简,化成一个三角函数式,即可知道结果.请参考图片.