已知|5-2x| (5-y)=0
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5x-4y=0;x=4y/5;x^2+y^2/x^2-y^2-x+y/x-y=(x²+y²-(x+y)²)/(x²-y²)=(x²+y
x+y=02x+1=0x=-0.5y=0.52(x+5y)=2*(-0.5+2.5)=4平方根=±2
很多数学符号,还是写出来方便.
x²+y²-2x+4y+5=0配方:(x-1)²+(y+2)²=0所以只有x-1=0且y+2=0∴x=1,y=-2∴(X^4-y^4)/(2x^2+xy-y
x²+y²-2x+4y+5=0(x²-2x+1)+(y²+4y+4)=0(x-1)²+(y+2)²=0x-1=0x=1y+2=0y=-2x+
x+y=02x+1=0x=-0.5y=0.52(x+5y)=2*(-0.5+2.5)=4平方根=±2
∵x²+y²-4x+2y+5=0x²-4x+4+y²+2y+1=0(x-2)²+(y+1)²=0x-2=0y+1=0∴x=2y=-14x
因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6
X^2表示平方X^2+4X+4+Y^2-2Y+1=0(X+2)^2+(Y-1)^2=0因为平方大于=0所以X+2=0Y-1=0X=-2Y=1X^2+Y^2=5
因为-5|x-2y|≥08|y-1\2|≥0而-5|x-2y|+8|y-1\2|=0所以-5|x-2y|=08|y-1\2|=0x-2y=0y-1/2=0解得x=1y=1/2
可能题有误.若x^2+y^2-4x-2y+5=0.(x-2)^2+(y-1)^2=0x=2,y=1根号x+y除以根号下x-y为根3
x-y=a+32x+y=53x=a+8x=(a+8)/3>0a>-8y=-(2a+1)/3-1/2所以a>-1/2
已知x^2+4y^2-4x+4y+5=0求((y^4-x^4)/(y-2x)(x+y))*((2x-y)/(xy-y^2))/((x^2+y^2)/y)的值答案:x²+4y²-4x
x²+4x+y²-2y+5=0x²+4x+4+y²-2y+1=0(x+2)²+(y-1)²=0所以x+2=0y-1=0则x=-2y=1所以x
x-5y=0x=5y所以(2x-3y)/(3x+6y)=(10y-3y)/(15y+6y)=7y/21y=1/3
这是线性规划问题,画图,三个约束条件的区域构成一个三角形,平移直线y=-x/2+z/4,z要最小,即直线的截距最小,向下平移,在点(3,-3)取到最小值,代入得z=-6,如果平移直线出现问题,那么你就
x-3y=0x=3y2x+5y/3x-2y=11y/7y=11/7
(x³+y³)+(x²y+xy²)+(x+y)=0(x+y)(x²-xy+y²)+xy(x+y)+(x+y)=0(x+y)(x²-
2x+y+3=xy,①若x=1,则y不存在,此时5x+4y无最值;②若x≠1,则y=(2x+3)/(x-1),M=5x+4y=5x+(8x+12)/(x-1)=(5x²+3x+12)/(x-