函数y=根号下sin(2x-π 4)的定义域-搜答案-拍题作业网

(1)y=sinx(根号下)+tanx(tanx不在根号下)要保证sinx>=0,tanx有意义即可.所以由sinx>=0得x属于[2k（Pi),2k（Pi)+(Pi)],（其中Pi表示圆周率的符号）

1.〔2kπ,π／2＋2kπ）2.〔－tan1,tan1〕

由题意可得sin(2x+π/6)

答案是这个,再问：具体过程再答：久等了~公式难打~若满意请采纳~

(1)y=√(2sinx+1)2sinx+1>=0sinx>=-1/2所以x取值范围为[-π/6+2kπ,7π/6+2kπ](k为整数)(2)y=√（16-x^2）+√（-cosx）16-x^2>=0

因为sin(cosx)>=0所以2nπ≤cosx≤(2n+1)π但cosx∈[-1,1],所以0≤cosx≤1,定义域为[(2n-1/2)π,(2n+1/2)π](n∈Z)

=2sin(2x)cos[2(x)]=sin(4x)周期0.5pi再问：那他是奇还是偶函数？

y＝（√3/2）sin（x＋π/2）＋cos（π/6－x）＝（√3/2）cosx＋cos（π/6）cosx＋sin（π/6）sinx＝（√3/2）cosx＋（√3/2）cosx＋（1/2）sinx＝√

把函数y=√[sin(π/3-2x)]看成y=√u(u≥0),u=sinv,v=π/3-2x的复合函数,√u是增函数,v=π/3-2x是减函数,∴y递增sinv递减,y的增区间由(2k+1/2)π

2sin(x+π/4）+1≥0sin(x+π/4)≥-1/22kπ-π/6≤x+π/4≤2kπ+7π/62kπ-5π/12≤x≤2kπ+11π/12[2kπ-5π/12,2kπ+11π/12],k∈Z

y=2cosxsin(x+π/3)-根号3*(sin^2)x+sinxcosx,后两项先提出一个sinx,然后括号内部分用叠加原理,得到y=2cosxsin(x+π/3)+2sinxcos(x+π/3

y=1/根号下1-sin^2x=1/根号下cos²xcos²x≠0x≠kπ+π/2

のz/のx=cos(y√x)·[y/(2√x)]=[y/(2√x)]cos(y√x)のz/のy=cos(y√x)·√x=√xcos(y√x)再问：谢谢您，您的根号是怎么打上的？

y'=-sin2x*(2x)'+cos√x*(√x)'=-2sin2x+cos√x/(2√x)

y=sin(2x-π/3)+根号3cos2x=sin2xcosπ/3-cos2xsinπ/3+2sinπ/3cos2x=sin2xcosπ/3+cos2xsinπ/3=sin(2x+π/3)1.振幅=

3sinx-2sin^2x-1>=0令sinx=tt范围为[-1,1]3t-2t^2-1>=0所以(t-1/2)(t-1)

(xe^x)'=e^x+xe^x(xe^x)''=2e^x+xe^x...归纳法,如果(xe^x)k阶导数是ke^x+xe^x则k+1阶导数就是ke^x+e^x+xe^x=(k+1)e^x+xe^x综

2sin(x+π/4)+1>=0sin(x+π/4)>=-1/2-π/3+2kπ