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将四个球随机的放入三个杯子中,以x表示杯子中球的最大个数,求x=2的概率

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将四个球随机的放入三个杯子中,以x表示杯子中球的最大个数,求x=2的概率
P(x=2)
= P(2 balls in 1 cup and 3rd ball is in the other cups)
= 4C1.3C2 .(1/4)(1/4).(3/4)
= 4.3.(1/4)(1/4).(3/4)
=9/16
再问: 答案是8/9,我算出来是2/3
再答: P(x=2) = P(2 balls in 1 cup and the other 2 balls in the other cups) = 3C1.4C2. (1/3)^2(2/3)^2 = 3. (6) (1/9)(4/9) = 8/9 3C1: choose 1 cup from 3 cups 4C2: 2balls in 1 cup and the other 2balls in other cups