设数列an的首项a1等于1,前n项和为sn,sn+1=2n
设数列an的首项a1等于1,前n项和为sn,sn+1=2n
设Sn是数列an的前n项和,已知a1=1,an=-Sn*Sn-1,(n大于等于2),则Sn=
设数列an的前n项和为Sn,a1=1,an=(Sn/n)+2(n-1)(n∈N*) 求证:数列an为等差数列,
已知数列an的首项a1=5,前n项和为Sn,且S(n+1)=2Sn+n+5(n∈N*),求数列{an}的前n项和Sn,设
设数列an的前n项和为Sn,已知a1=1,Sn+1=4an+2
设数列an的前n项和为Sn.已知首项a1等于3,且S(n+1)+Sn=2a(n+1)求通项公式以及前n项和sn
设数列{an}的前n项和为Sn,若a1=1,Sn=2an+Sn+(n∈N+),则a6=
设数列{an}的前n项和为Sn,已知首项a1=3,且Sn+1+Sn=2an+1,试求此数列的通项公式an及前n项和Sn
设数列an的前n项和为Sn,a1=1 ,an = 2Sn²/2Sn-1 (n≥2)
设数列{an}的前n项和为Sn,a1=10,a(n+1)=9Sn+10
数列{an}的前n项和为Sn,a1=1,an+1=2Sn(n∈N*)
设数列an的前n项和为Sn,已知a1=1,(2Sn)/n=a(n+1)-1/3n^2-n-2/3