[(sinθ+tanθ)/(cscθ+cotθ)]^2=(sin^2θ+tan^2θ)/(csc^2θ+cot^2θ)
[(sinθ+tanθ)/(cscθ+cotθ)]^2=(sin^2θ+tan^2θ)/(csc^2θ+cot^2θ)
tanθ+cotθ=3,则tan^2θ+secθcscθ+cot^2θ的值为
证明:tanθ-cotθ/secθ-cscθ=secθ+cscθ/tanθ+cotθ
求证:sin^2θtanθ+cos^2θcotθ+2sinθcosθ=tanθ+cotθ
化简:cos^2θcotθ+sin^2θtanθ+2cosθsinθ
证明1-2cos^2θ/tanθ-cotθ=sinθcosθ
π/2的6个三角函数值 sin cos tan sec csc cot
sinθ-cosθ=1/2,则tanθ+cotθ=
已知sinθ+cosθ=√2,则tanθ+cotθ=?
已知tanθ+cotθ=2,求sin^3θ-cos^3θ的值
sinΘ-cosΘ=1/2,求tanΘ+cotΘ
证明tan^2α-cot^2α/sin^2α-cos^2α=sec^2α+csc^2α