int a[3][3]={1,2,3,4,5,6,7,8,9} ,s=0,*p=a,i
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int a[3][3]={1,2,3,4,5,6,7,8,9} ,s=0,*p=a,i
int a[3][3]={1,2,3,4,5,6,7,8,9} ,s=0,*p=a,i; for(i=0;i
int a[3][3]={1,2,3,4,5,6,7,8,9} ,s=0,*p=a,i; for(i=0;i
int a[3][3]={{1,2,3},{4,5,6},{7,8,9}} ;
int s=0, i;
int *p=a[0][0];
for(i=0;i 再答: 这是一种解法。程序主要出在多维数组的指针定义用法不准确。
再答: int a[3][3]={{1,2,3},{4,5,6},{7,8,9}} ;
int s=0;
int *p=&a[0][0];
for(int i=0;i
int s=0, i;
int *p=a[0][0];
for(i=0;i 再答: 这是一种解法。程序主要出在多维数组的指针定义用法不准确。
再答: int a[3][3]={{1,2,3},{4,5,6},{7,8,9}} ;
int s=0;
int *p=&a[0][0];
for(int i=0;i
int a[3][3]={{1,2,3},{4,5,6},{7,8,9}}; int **p; p=(int**)a;
int a[3][3]={1,2,3,4,5,6,7,8,9} ,s=0,*p=a,i
main(){int x[]={1,2,3,4,5,6,7,8,9}int s,i,*p;s=0;p=&x[0];fpr
C语言 int a[ ]={0,1,2,3,4,5,6,7,8,9},*p=a,i; 0
int a[]={1,2,3,4,5,6,7,8,9},*p; for(p=a,p
#include main(){int a[]={1,2,3,4,5,6,7,8,9,0},*p; p=a; print
C语言 int a[ ]={0,1,2,3,4,5,6,7,8,9},*p=a *p=a 是不是相当于 *(p=a)
{ int a[]={1,2,3,4,5,6}; int*p; p=a; printf("%d\n",*p); prin
有如下程序,int a[10]={1,2,3,4,5,6,7,8,9,10}; int *p=&a[3],b;b=p[5
struct st{int x,int*y;}*p; int s[]={5,6,7,8} st a[]={10,&s[0
int a[3][5]={{1,2},{6,4},{3,4,5}}; int (*p)[5] = a; 求*(*p+1)
int a[ ][3]={1,2,3,4,5,6,7,8,9,10,11,12};int*p=a;求 *(*(a+2)+