作业帮求值sin25π/6+cos25π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-
来源：学生作业帮 编辑：拍题作业网作业帮 分类：数学作业 时间：2024/04/30 05:00:46
求值sin25π/6+cos25π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-5π/6)×cos(-5π/3)
sin25π/6+cos25π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-5π/6)×cos(-5π/3)
=sin(4π+π/6)+cos(8π+π/3)+tan(-25π/4+6π)+sin(-7π/3+2π)×cos(-13π/6+2π)-sin(π-π/6)×cos(-5π/3+2π)
=sinπ/6+cosπ/3+tan(-π/4)+sin(-π/3)×cos(-π/6)-sin(π/6)×cos(π/3)
=sinπ/6+cosπ/3-tanπ/4-sinπ/3×cosπ/6-sin(π/6)×cos(π/3)
=1/2+1/2-1-√3/2×√3/2-1/2×1/2
=-3/4-1/4
=-1
=sin(4π+π/6)+cos(8π+π/3)+tan(-25π/4+6π)+sin(-7π/3+2π)×cos(-13π/6+2π)-sin(π-π/6)×cos(-5π/3+2π)
=sinπ/6+cosπ/3+tan(-π/4)+sin(-π/3)×cos(-π/6)-sin(π/6)×cos(π/3)
=sinπ/6+cosπ/3-tanπ/4-sinπ/3×cosπ/6-sin(π/6)×cos(π/3)
=1/2+1/2-1-√3/2×√3/2-1/2×1/2
=-3/4-1/4
=-1
求值sin25π/6+cos25π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-
计算：sin25π/6+cos25π/4+tan(-25π/4)+sin(-26π/3)
sin25π/6+cos10π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)=
求sin25π/6+cos5π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-5π
sin25π/4+cos25π/3+tan(-25π/4)=
sin25/6pai+cos25/3pai+tan(-25/4pai)
1.已知tan2分之α=2,求值:⑴ tan(α+4分之π)；⑵ （6sinα+cosα）/（3sinα-2cosα）
求值：1.cos(-14π/3) 2.tan（35π/6） 3.sin（-25π/6）
求值：sin(π/4)cos(19π/6)tan(21π/4)急!
求值：⑴sin(-19π/3)*cos(19π/6)
化简求值,sin(2a-π)tan(π+a)cota/cos(π-a)tan(3π-a)
cosπ/3+tanπ/4+3tan²π/6+sinπ/2+cosπ+sin3π/2等于?.