用C语言计算log(5)log(3)-log(2))/sin(π/3)=

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用C语言计算log(5)log(3)-log(2))/sin(π/3)=
#include
#include
int main()
{
int a=5,b=3,c=2;
double y;
y=(log(a)log(b)-log(c))/sin(π/b);
printf("(log(5)log(3)-log(2))/sin(π/3)=%ld",y);
return 0;
}
x这哪里错了?

#include
#include
const double pi=3.141592;
int main()
{
int a=5,b=3,c=2;
double y;
y=(log(a)*log(b)-log(c))/sin(pi/b);
printf("(log(5)log(3)-log(2))/sin(π/3)=%ld\n",y);
return 0;
}
这是通过编译的

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