1设f(x)=(2x∕1+x)?(2x∕1-x),求limf(x)x→1,limf(x)x→∞
1设f(x)=(2x∕1+x)?(2x∕1-x),求limf(x)x→1,limf(x)x→∞
设极限limf(x) (x→1)存在,且f(x)=3x²+2xlimf(x) (x→1),求f(x)
设f(0)=0,f'(0)=1,求limf[(2x)-f(-3x)]÷x x→0
设f(x)在区间(-∞,+∞)内单调增加,limf(x)=1(x→0),证明f(x)在x=0处连续
lim(1+f(x)sinx)^1\2-1)/x=2,x->0,求limf(x)
limf(x)(x趋向于0)=f(0)=1,f(2x)-f(x)=x^2,求f(x)
f (x)=x/1+x当x->-1时,limf(x)的极限不存在?求证明
求f(x)=(x^3+x^2-3x+1)/(x^2-3x+2)的连续区间,并求极限limf(x) x→3
已知limx/f(4x)=1,求limf(2x)/x x趋近0
已知f(0)=0,f'(0)=1,求极限limf(2x)/x (x趋于0).
设f(x)在0到正无穷大上可导,f(x)>0,limf(x)=1(x趋向正无穷大),若lim[f(x+nx)/f(x)]
设函数f(x-1)=x^2+2x-4,则limf(x)=?(x->0 )