已知x²+4y²-6x+8y+13=0,求x-y/x+y的值.

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x²+4y²-6x+8y+16=0
(x²-6x+9)+4(y²+2y+1)=0
(x-3)²+4(y+1)²=0
x-3=0,y+1=0
x=3,y=-1
(x-y)/(x+y)
=[3-(-1)]/[3+(-1)]
=4/2
=2
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