问道数列题.设数列an满足a1+2a2+3a3+...+nan=2^n(n属于正自然数),则数列an的通项是?
问道数列题.设数列an满足a1+2a2+3a3+...+nan=2^n(n属于正自然数),则数列an的通项是?
设数列{an}满足a1+2a2+3a3+.+nan=n(n+1)(n+2)
设数列an满足a1+2a2+3a3+.+nan=2^n(n属于N*)求数列an的通项公式 设bn=n^2an,求数列bn
数列an满足a1+2a2+3a3+...+nan=(n+1)(n+2) 求通项an
已知数列an满足a1+2a2+3a3+...+nan=n(n+1)*(n+2),则数列an的前n项和Sn=?
若数列{an}满足a1+2a2+3a3+~~+nan=n(n+1)(2n+1),则an=
已知数列{an}满足:a1+2a2+3a3+...+nan=(2n-1)*3^n(n属于正整数)求数列{an}得通项公式
设数列{an}满足a1+3 a2+3^2 a3+……+3^n-1 an=n/3,a属于N* 求数列{an}的通项
已知数列{an}满足a1+2a2+3a3+…+nan=n(n+1)(n+2),则a1+a2+a3+…+an=多少?
已知数列(an)满足a1+2a2+3a3+...+nan=n(n+1)(n+2)求an
设数列an满足a1+2a2+3a3+.+nan=2^n 1求数列a的通项 2设bn=n^2an 求数列的前n项和Sn求大
已知数列{an}满足a1+2a2+3a3+...+nan=n(n+1)(2n+1),则该数列an=?