lim[2n+(an^2-2n+1)/(bn+2)]=1,则点(a,b)坐标为
lim[2n+(an^2-2n+1)/(bn+2)]=1,则点(a,b)坐标为
若lim[2n+(an^2+2n+1)/(bn+1)=1,则a+b
a,b为常数.lim(n->无穷)an^2+bn+2/2n-1=3 求a,b
等差数列{an},{bn}的前n项和分别为An,Bn,切An/Bn=2n/3n+1,求lim(n→∞)an/bn
lim[{根号(n^2+an)}-(bn+1)]=b,求a
若lim(2n+(an^2-2n+1)/(bn+2))=1 求a/b的值
lim (n→∞) [(an^2+bn+c)/(2n+5)]=3,求a,b
若lim[(an^2+bn+c)/(2n-3)]=-2,则a+b=
a(n+1)=2an-a(n-1) 3bn-b(n-1)=n
lim(n->无穷)[(3n^2+cn+1)/(an^2+bn)-4n]=5
已知点pn(an,bn)满足an+1=anb n+1,b n+1=bn/1-4an^2,且p1的坐标为(1,-1).
已知a b 是常数 lim(a根号(2n^2+n+1) -bn))=1 则a+b=