数学竞赛题:若实数x,y满足方程组xy+x+y+7=0,3x+3y=9+2xy,则x2y+xy2=?
数学竞赛题:若实数x,y满足方程组xy+x+y+7=0,3x+3y=9+2xy,则x2y+xy2=?
若实数x,y满足xy+x+y+7=0,3x+3y=9+2xy,则x2y+xy2=______.
若x-y=3,xy=-2,则xy2-x2y的值是______.
已知实数x、y满足x+y+xy=9,x2y+xy2=20,求x2+y2的值.
已知x、y均为实数,且满足xy+x+y=17,x2y+xy2=66,求x2+y2
已知x+y=6,xy=-3,则x2y+xy2=
若实数x,y满足xy>0且x2y=2,则xy+x2的最小值是( )
已知x+y=-5,xy=7,求x2y+xy2-x-y的值.
已知x、y均为实数,且满足xy+x+y=17,x2y+xy2=66,则x4+x3y+x2y2+xy3+y4=______
若x+y=5,xy=6,则x2y+xy2的值为______.
若x+y=2,xy=-4,求x2y+xy2+1的值
已知(x+3)2+▕x-y+10▏=0求代数式5x2y-【2x2-(3xy-xy2)-3x2】-2xy2-y2的值.